Wednesday, June 21, 2006

triplet problem[S]

(a,b,c) form a triplet if all a,b,c are natural numbers and a^2=b^2+c^2
prove that (1)one among the triplet is even.(2)one among the triplet is a multiple of 3.
[S]

1 comment:

talegari (ತಾಳೆಗರಿ) said...

solution:
(1)suppose none were even then odd+odd=odd which is false.
(2)suppose a and b=3k+1 or 3k+2.
in all four cases c=3k.