(a,b,c) form a triplet if all a,b,c are natural numbers and a^2=b^2+c^2
prove that (1)one among the triplet is even.(2)one among the triplet is a multiple of 3.
[S]
Wednesday, June 21, 2006
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Simple math problems for recreation and research
"And yet the relation appears,
A small relation expanding like the shade
of a cloud on the sand,a shape on side of the hill"
-Wallace Stevens,'Connoisseur of Chaos'
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1 comment:
solution:
(1)suppose none were even then odd+odd=odd which is false.
(2)suppose a and b=3k+1 or 3k+2.
in all four cases c=3k.
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